12x^2-2x-30=2(2x-3)(4x+1)

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Solution for 12x^2-2x-30=2(2x-3)(4x+1) equation: 



12x^2-2x-30=2(2x-3)(4x+1)

We move all terms to the left:

12x^2-2x-30-(2(2x-3)(4x+1))=0

We multiply parentheses ..

12x^2-(2(+8x^2+2x-12x-3))-2x-30=0



We calculate terms in parentheses: -(2(+8x^2+2x-12x-3)), so:

2(+8x^2+2x-12x-3)

We multiply parentheses

16x^2+4x-24x-6

We add all the numbers together, and all the variables

16x^2-20x-6

Back to the equation:

-(16x^2-20x-6)



We add all the numbers together, and all the variables

12x^2-2x-(16x^2-20x-6)-30=0

We get rid of parentheses

12x^2-16x^2-2x+20x+6-30=0

We add all the numbers together, and all the variables

-4x^2+18x-24=0

a = -4; b = 18; c = -24;
Δ = b2-4ac
Δ = 182-4·(-4)·(-24)
Δ = -60
Delta is less than zero, so there is no solution for the equation

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